0 Replies Latest reply: May 4, 2012 9:26 AM by ~= ziggy =~ RSS

RestEasy - Is it possible to extract the request exactly as it came in?

~= ziggy =~ Newbie

I have a web service that is processed on the Spring end as follows:

    @POST
   
@Path("/processRequest")
   
@Consumes("multipart/mixed")
   
@ResponseStatus(HttpStatus.OK)
   
public String processRequest(@Context ServletContext servletContext, MultipartInput input) {

       
return addAccout(servletContext, input);
   
}

The request will come in as a multipart/mixed request and will look something like this:

--productBoundary
Content-Type: text/xml

<?xml version="1.0" encoding="UTF-8"?>
<product>
    
<name>ProductA</name>
</product>

--productBoundary
Content-Type: text/xml

ZGF0YRBAAABn5
///////////////5///Z+fn///n////////5////////2f//2f//+f//+f////n/
///////52f//////2f//////2f/////5////////+f/////Z+f///////////////9n//9nZ/9n////5+f///9
<snip>
//+f//////2f/////////5//n//////////9n

--productBoundary--

The request will come in as a mutipart/mixed. I can use Resteasy's object shown in the processRequest's method parameters to extract each part of the multipart/mixed message. What i would like to do though is to get the message as it is unmodified with its headers and everything else. Is this possible?

 

I need to be able to store the request exactly as it came in. Using the RestEasy MultipartInput structure means i have modified the request. Is there anyway i can get the request as it came in with all its headers without modifying it?